Optimal. Leaf size=73 \[ -\frac {i \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^3}+\frac {2 x \log \left (1+e^{2 i (a+b x)}\right )}{b^2}+\frac {x^2 \tan (a+b x)}{b}-\frac {i x^2}{b}-\frac {x^3}{3} \]
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Rubi [A] time = 0.11, antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3720, 3719, 2190, 2279, 2391, 30} \[ -\frac {i \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^3}+\frac {2 x \log \left (1+e^{2 i (a+b x)}\right )}{b^2}+\frac {x^2 \tan (a+b x)}{b}-\frac {i x^2}{b}-\frac {x^3}{3} \]
Antiderivative was successfully verified.
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Rule 30
Rule 2190
Rule 2279
Rule 2391
Rule 3719
Rule 3720
Rubi steps
\begin {align*} \int x^2 \tan ^2(a+b x) \, dx &=\frac {x^2 \tan (a+b x)}{b}-\frac {2 \int x \tan (a+b x) \, dx}{b}-\int x^2 \, dx\\ &=-\frac {i x^2}{b}-\frac {x^3}{3}+\frac {x^2 \tan (a+b x)}{b}+\frac {(4 i) \int \frac {e^{2 i (a+b x)} x}{1+e^{2 i (a+b x)}} \, dx}{b}\\ &=-\frac {i x^2}{b}-\frac {x^3}{3}+\frac {2 x \log \left (1+e^{2 i (a+b x)}\right )}{b^2}+\frac {x^2 \tan (a+b x)}{b}-\frac {2 \int \log \left (1+e^{2 i (a+b x)}\right ) \, dx}{b^2}\\ &=-\frac {i x^2}{b}-\frac {x^3}{3}+\frac {2 x \log \left (1+e^{2 i (a+b x)}\right )}{b^2}+\frac {x^2 \tan (a+b x)}{b}+\frac {i \operatorname {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{b^3}\\ &=-\frac {i x^2}{b}-\frac {x^3}{3}+\frac {2 x \log \left (1+e^{2 i (a+b x)}\right )}{b^2}-\frac {i \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^3}+\frac {x^2 \tan (a+b x)}{b}\\ \end {align*}
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Mathematica [B] time = 6.19, size = 189, normalized size = 2.59 \[ \frac {\csc (a) \sec (a) \left (b^2 x^2 e^{-i \tan ^{-1}(\cot (a))}-\frac {\cot (a) \left (i \text {Li}_2\left (e^{2 i \left (b x-\tan ^{-1}(\cot (a))\right )}\right )+i b x \left (-2 \tan ^{-1}(\cot (a))-\pi \right )-2 \left (b x-\tan ^{-1}(\cot (a))\right ) \log \left (1-e^{2 i \left (b x-\tan ^{-1}(\cot (a))\right )}\right )-2 \tan ^{-1}(\cot (a)) \log \left (\sin \left (b x-\tan ^{-1}(\cot (a))\right )\right )-\pi \log \left (1+e^{-2 i b x}\right )+\pi \log (\cos (b x))\right )}{\sqrt {\cot ^2(a)+1}}\right )}{b^3 \sqrt {\csc ^2(a) \left (\sin ^2(a)+\cos ^2(a)\right )}}+\frac {x^2 \sec (a) \sin (b x) \sec (a+b x)}{b}-\frac {x^3}{3} \]
Warning: Unable to verify antiderivative.
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fricas [B] time = 0.53, size = 144, normalized size = 1.97 \[ -\frac {2 \, b^{3} x^{3} - 6 \, b^{2} x^{2} \tan \left (b x + a\right ) - 6 \, b x \log \left (-\frac {2 \, {\left (i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1}\right ) - 6 \, b x \log \left (-\frac {2 \, {\left (-i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1}\right ) - 3 i \, {\rm Li}_2\left (\frac {2 \, {\left (i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1} + 1\right ) + 3 i \, {\rm Li}_2\left (\frac {2 \, {\left (-i \, \tan \left (b x + a\right ) - 1\right )}}{\tan \left (b x + a\right )^{2} + 1} + 1\right )}{6 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{2} \tan \left (b x + a\right )^{2}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.35, size = 108, normalized size = 1.48 \[ -\frac {x^{3}}{3}+\frac {2 i x^{2}}{b \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )}-\frac {2 i x^{2}}{b}-\frac {4 i a x}{b^{2}}-\frac {2 i a^{2}}{b^{3}}+\frac {2 x \ln \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )}{b^{2}}-\frac {i \polylog \left (2, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{b^{3}}+\frac {4 a \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.35, size = 256, normalized size = 3.51 \[ \frac {i \, b^{3} x^{3} + 6 \, {\left (b x \cos \left (2 \, b x + 2 \, a\right ) + i \, b x \sin \left (2 \, b x + 2 \, a\right ) + b x\right )} \arctan \left (\sin \left (2 \, b x + 2 \, a\right ), \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) + {\left (i \, b^{3} x^{3} - 6 \, b^{2} x^{2}\right )} \cos \left (2 \, b x + 2 \, a\right ) - 3 \, {\left (\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right )} {\rm Li}_2\left (-e^{\left (2 i \, b x + 2 i \, a\right )}\right ) + {\left (-3 i \, b x \cos \left (2 \, b x + 2 \, a\right ) + 3 \, b x \sin \left (2 \, b x + 2 \, a\right ) - 3 i \, b x\right )} \log \left (\cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (2 \, b x + 2 \, a\right )^{2} + 2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) - {\left (b^{3} x^{3} + 6 i \, b^{2} x^{2}\right )} \sin \left (2 \, b x + 2 \, a\right )}{-3 i \, b^{3} \cos \left (2 \, b x + 2 \, a\right ) + 3 \, b^{3} \sin \left (2 \, b x + 2 \, a\right ) - 3 i \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int x^2\,{\mathrm {tan}\left (a+b\,x\right )}^2 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{2} \tan ^{2}{\left (a + b x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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